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cpp2ffi.lua: remove explicit keyword, get template_type from parser.templates instead of string substitution (solves issues #140 and #141)

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Victor Bombi
2020-06-30 09:39:48 +02:00
parent 8c5bda8548
commit 2f4c2c03db
1 changed files with 12 additions and 8 deletions
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20
generator/cpp2ffi.lua
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@@ -430,6 +430,7 @@ local function parseFunction(self,stname,lineorig,namespace,locat)
line = line:gsub("static","")
line = line:gsub("inline","")
line = line:gsub("mutable","")
line = line:gsub("explicit","")
--skip operator
if line:match("operator") then return end
--skip template
@@ -1075,19 +1076,22 @@ function M.Parser()
else
--split type name1,name2; in several lines
local typen,rest = line:match("%s*([^,]+)%s(%S+[,;])")
--local template_type = typen:match("/%*<(.+)>%*/")
--if template_type then typen = typen:match("(.+)/%*") end
if not typen then -- Lets try Type*name
typen,rest = line:match("([^,]+%*)(%S+[,;])")
end
local template_type
for k,v in pairs(self.templates) do
template_type = typen:match(k.."_(.+)")
if template_type then break end
end
if template_type then
template_type = template_type:gsub("_"," ")
template_type = template_type:gsub("Ptr","%*")
local template_type2 = typen:match(k.."_(.+)")
if template_type2 then
for k1,k2 in pairs(v) do
if template_type2==k2 then
template_type=k1
break
end
end
assert(template_type)
break
end
end
for name in rest:gmatch("([^%s,;]+)%s?[,;]") do
--unnamed unions